x86: Fix the mystery of printch() during 64-bit boot
At present in arch_setup_gd() it calls printch(' ') at the end which has been a mystery for a long time as without such call the 64-bit U-Boot just does not boot at all. In fact this is due to the bug that board_init_f() was called with boot_flags not being set. Hence whatever value being there in the rdi register becomes the boot_flags if without such magic call. With a printch(' ') call the rdi register is initialized as 0x20 and this value seems to be sane enough for the whole boot process. Signed-off-by: Bin Meng <bmeng.cn@gmail.com> Reviewed-by: Heinrich Schuchardt <xypron.glpk@gmx.de>
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@ -20,6 +20,7 @@ _start:
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call board_init_f_init_reserve
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xor %rdi, %rdi
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call board_init_f
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call board_init_f_r
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@ -19,24 +19,6 @@ struct global_data *global_data_ptr = (struct global_data *)~0;
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void arch_setup_gd(gd_t *new_gd)
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{
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global_data_ptr = new_gd;
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/*
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* TODO(sjg@chromium.org): For some reason U-Boot does not boot
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* without this line. It fails to start up U-Boot proper and instead
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* restarts SPL. Need to figure out why:
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*
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* U-Boot SPL 2017.01
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*
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* U-Boot SPL 2017.01
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* CPU: Intel(R) Core(TM) i5-3427U CPU @ 1.80GHz
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* Trying to boot from SPIJumping to 64-bit U-Boot: Note many
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* features are missing
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*
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* U-Boot SPL 2017.01
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*/
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#ifdef CONFIG_DEBUG_UART
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printch(' ');
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#endif
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}
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int cpu_has_64bit(void)
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