net: dsa: avoid fast ageing twice when port leaves a bridge

Drivers that support both the toggling of address learning and dynamic
FDB flushing (mv88e6xxx, b53, sja1105) currently need to fast-age a port
twice when it leaves a bridge:

- once, when del_nbp() calls br_stp_disable_port() which puts the port
  in the BLOCKING state
- twice, when dsa_port_switchdev_unsync_attrs() calls
  dsa_port_clear_brport_flags() which disables address learning

The knee-jerk reaction might be to say "dsa_port_clear_brport_flags does
not need to fast-age the port at all", but the thing is, we still need
both code paths to flush the dynamic FDB entries in different situations.
When a DSA switch port leaves a bonding/team interface that is (still) a
bridge port, no del_nbp() will be called, so we rely on
dsa_port_clear_brport_flags() function to restore proper standalone port
functionality with address learning disabled.

So the solution is just to avoid double the work when both code paths
are called in series. Luckily, DSA already caches the STP port state, so
we can skip flushing the dynamic FDB when we disable address learning
and the STP state is one where no address learning takes place at all.
Under that condition, not flushing the FDB is safe because there is
supposed to not be any dynamic FDB entry at all (they were flushed
during the transition towards that state, and none were learned in the
meanwhile).

Signed-off-by: Vladimir Oltean <vladimir.oltean@nxp.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Vladimir Oltean 2021-08-09 01:56:49 +03:00 committed by David S. Miller
parent a4ffe09fc2
commit bee7c577e6

View File

@ -699,7 +699,9 @@ int dsa_port_bridge_flags(struct dsa_port *dp,
if (learning == dp->learning)
return 0;
if (dp->learning && !learning)
if ((dp->learning && !learning) &&
(dp->stp_state == BR_STATE_LEARNING ||
dp->stp_state == BR_STATE_FORWARDING))
dsa_port_fast_age(dp);
dp->learning = learning;