PCI / PM: Skip bridges in pci_enable_wake()
PCI bridges only have a reason to generate wakeup signals on behalf of devices below them, so avoid preparing bridges for wakeup directly in pci_enable_wake(). Also drop the pci_has_subordinate() check from pci_pm_default_resume() as this will be done by pci_enable_wake() itself now. Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com> Reviewed-by: Mika Westerberg <mika.westerberg@linux.intel.com> Acked-by: Bjorn Helgaas <bhelgaas@google.com>
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@ -647,8 +647,6 @@ static int pci_legacy_resume(struct device *dev)
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static void pci_pm_default_resume(struct pci_dev *pci_dev)
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static void pci_pm_default_resume(struct pci_dev *pci_dev)
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{
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{
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pci_fixup_device(pci_fixup_resume, pci_dev);
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pci_fixup_device(pci_fixup_resume, pci_dev);
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if (!pci_has_subordinate(pci_dev))
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pci_enable_wake(pci_dev, PCI_D0, false);
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pci_enable_wake(pci_dev, PCI_D0, false);
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}
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}
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@ -1912,6 +1912,13 @@ int pci_enable_wake(struct pci_dev *dev, pci_power_t state, bool enable)
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{
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{
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int ret = 0;
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int ret = 0;
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/*
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* Bridges can only signal wakeup on behalf of subordinate devices,
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* but that is set up elsewhere, so skip them.
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*/
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if (pci_has_subordinate(dev))
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return 0;
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/* Don't do the same thing twice in a row for one device. */
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/* Don't do the same thing twice in a row for one device. */
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if (!!enable == !!dev->wakeup_prepared)
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if (!!enable == !!dev->wakeup_prepared)
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return 0;
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return 0;
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