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sched: Fix clock_gettime(CLOCK_[PROCESS/THREAD]_CPUTIME_ID) monotonicity

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If a task has been dequeued, it has been accounted.  Do not project
cycles that may or may not ever be accounted to a dequeued task, as
that may make clock_gettime() both inaccurate and non-monotonic.

Protect update_rq_clock() from slight TSC skew while at it.

Signed-off-by: Mike Galbraith <umgwanakikbuti@gmail.com>
Cc: kosaki.motohiro@jp.fujitsu.com
Cc: pjt@google.com
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/1403588980.29711.11.camel@marge.simpson.net
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Mike Galbraith 2014-06-24 07:49:40 +02:00 committed by Ingo Molnar
parent c06f04c704
commit 4036ac1567
1 changed files with 11 additions and 2 deletions
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13
kernel/sched/core.c
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@ -139,6 +139,8 @@ void update_rq_clock(struct rq *rq)
return;
delta = sched_clock_cpu(cpu_of(rq)) - rq->clock;
if (delta < 0)
return;
rq->clock += delta;
update_rq_clock_task(rq, delta);
}
@ -2431,7 +2433,12 @@ static u64 do_task_delta_exec(struct task_struct *p, struct rq *rq)
{
u64 ns = 0;
if (task_current(rq, p)) {
/*
* Must be ->curr _and_ ->on_rq. If dequeued, we would
* project cycles that may never be accounted to this
* thread, breaking clock_gettime().
*/
if (task_current(rq, p) && p->on_rq) {
update_rq_clock(rq);
ns = rq_clock_task(rq) - p->se.exec_start;
if ((s64)ns < 0)
@ -2474,8 +2481,10 @@ unsigned long long task_sched_runtime(struct task_struct *p)
* If we race with it leaving cpu, we'll take a lock. So we're correct.
* If we race with it entering cpu, unaccounted time is 0. This is
* indistinguishable from the read occurring a few cycles earlier.
* If we see ->on_cpu without ->on_rq, the task is leaving, and has
* been accounted, so we're correct here as well.
*/
if (!p->on_cpu)
if (!p->on_cpu || !p->on_rq)
return p->se.sum_exec_runtime;
#endif