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std.Build.Step.Compile: restore previous step name

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Print using the target query rather than the resolved target. This makes
it print "native" when compiling for the native target.
This commit is contained in:
Andrew Kelley 2023-12-18 18:18:02 -07:00
parent 4b667e7362
commit ca77c3bacc
1 changed files with 3 additions and 2 deletions
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5
lib/std/Build/Step/Compile.zig
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@ -251,7 +251,8 @@ pub fn create(owner: *std.Build, options: Options) *Compile {
else
owner.fmt("{s} ", .{name});
const target = options.root_module.target.?.result;
const resolved_target = options.root_module.target.?;
const target = resolved_target.result;
const step_name = owner.fmt("{s} {s}{s} {s}", .{
switch (options.kind) {
@ -262,7 +263,7 @@ pub fn create(owner: *std.Build, options: Options) *Compile {
},
name_adjusted,
@tagName(options.root_module.optimize orelse .Debug),
target.zigTriple(owner.allocator) catch @panic("OOM"),
resolved_target.query.zigTriple(owner.allocator) catch @panic("OOM"),
});
const out_filename = std.zig.binNameAlloc(owner.allocator, .{