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ftrace: Simplify the calculation of page number for ftrace_page->records some more

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Commit b40c6eabfc ("ftrace: Simplify the calculation of page number for
ftrace_page->records") simplified the calculation of the number of pages
needed for each page group without having any empty pages, but it can be
simplified even further.

Link: https://lore.kernel.org/lkml/CAHk-=wjt9b7kxQ2J=aDNKbR1QBMB3Hiqb_hYcZbKsxGRSEb+gQ@mail.gmail.com/

Suggested-by: Linus Torvalds <torvalds@linux-foundation.org>
Signed-off-by: Steven Rostedt (VMware) <rostedt@goodmis.org>
This commit is contained in:
Steven Rostedt (VMware) 2021-04-01 16:40:32 -04:00
parent db42523b4f
commit ceaaa12904
1 changed files with 2 additions and 8 deletions
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10
kernel/trace/ftrace.c
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@ -3156,15 +3156,9 @@ static int ftrace_allocate_records(struct ftrace_page *pg, int count)
if (WARN_ON(!count))
return -EINVAL;
/* We want to fill as much as possible, with no empty pages */
pages = DIV_ROUND_UP(count, ENTRIES_PER_PAGE);
order = get_count_order(pages);
/*
* We want to fill as much as possible. No more than a page
* may be empty.
*/
if (!is_power_of_2(pages))
order--;
order = fls(pages) - 1;
again:
pg->records = (void *)__get_free_pages(GFP_KERNEL | __GFP_ZERO, order);