mirror of
https://github.com/torvalds/linux.git
synced 2024-11-10 22:21:40 +00:00
perf bench: Add sched-pipe.c: Benchmark for pipe() system call
This patch adds bench/sched-pipe.c. bench/sched-pipe.c is a benchmark program to measure performance of pipe() system call. This benchmark is based on pipe-test-1m.c by Ingo Molnar: http://people.redhat.com/mingo/cfs-scheduler/tools/pipe-test-1m.c Example of use: % perf bench sched pipe (executing 1000000 pipe operations between two tasks) Total time:4.499 sec 4.499179 usecs/op 222262 ops/sec % perf bench sched pipe -s -l 1000 0.015 Signed-off-by: Hitoshi Mitake <mitake@dcl.info.waseda.ac.jp> Cc: Rusty Russell <rusty@rustcorp.com.au> Cc: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Mike Galbraith <efault@gmx.de> Cc: Arnaldo Carvalho de Melo <acme@redhat.com> Cc: fweisbec@gmail.com Cc: Jiri Kosina <jkosina@suse.cz> LKML-Reference: <1257381097-4743-4-git-send-email-mitake@dcl.info.waseda.ac.jp> Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
parent
e27454cc63
commit
c7d9300f36
113
tools/perf/bench/sched-pipe.c
Normal file
113
tools/perf/bench/sched-pipe.c
Normal file
@ -0,0 +1,113 @@
|
||||
/*
|
||||
*
|
||||
* builtin-bench-pipe.c
|
||||
*
|
||||
* pipe: Benchmark for pipe()
|
||||
*
|
||||
* Based on pipe-test-1m.c by Ingo Molnar <mingo@redhat.com>
|
||||
* http://people.redhat.com/mingo/cfs-scheduler/tools/pipe-test-1m.c
|
||||
* Ported to perf by Hitoshi Mitake <mitake@dcl.info.waseda.ac.jp>
|
||||
*
|
||||
*/
|
||||
|
||||
#include "../perf.h"
|
||||
#include "../util/util.h"
|
||||
#include "../util/parse-options.h"
|
||||
#include "../builtin.h"
|
||||
#include "bench.h"
|
||||
|
||||
#include <unistd.h>
|
||||
#include <stdio.h>
|
||||
#include <stdlib.h>
|
||||
#include <signal.h>
|
||||
#include <sys/wait.h>
|
||||
#include <linux/unistd.h>
|
||||
#include <string.h>
|
||||
#include <errno.h>
|
||||
#include <assert.h>
|
||||
#include <sys/time.h>
|
||||
|
||||
#define LOOPS_DEFAULT 1000000
|
||||
static int loops = LOOPS_DEFAULT;
|
||||
static int simple = 0;
|
||||
|
||||
static const struct option options[] = {
|
||||
OPT_INTEGER('l', "loop", &loops,
|
||||
"Specify number of loops"),
|
||||
OPT_BOOLEAN('s', "simple-output", &simple,
|
||||
"Do simple output (this maybe useful for"
|
||||
"processing by scripts or graph tools like gnuplot)"),
|
||||
OPT_END()
|
||||
};
|
||||
|
||||
static const char * const bench_sched_pipe_usage[] = {
|
||||
"perf bench sched pipe <options>",
|
||||
NULL
|
||||
};
|
||||
|
||||
int bench_sched_pipe(int argc, const char **argv,
|
||||
const char *prefix __used)
|
||||
{
|
||||
int pipe_1[2], pipe_2[2];
|
||||
int m = 0, i;
|
||||
struct timeval start, stop, diff;
|
||||
unsigned long long result_usec = 0;
|
||||
|
||||
/*
|
||||
* why does "ret" exist?
|
||||
* discarding returned value of read(), write()
|
||||
* causes error in building environment for perf
|
||||
*/
|
||||
int ret;
|
||||
pid_t pid;
|
||||
|
||||
argc = parse_options(argc, argv, options,
|
||||
bench_sched_pipe_usage, 0);
|
||||
|
||||
assert(!pipe(pipe_1));
|
||||
assert(!pipe(pipe_2));
|
||||
|
||||
pid = fork();
|
||||
assert(pid >= 0);
|
||||
|
||||
gettimeofday(&start, NULL);
|
||||
|
||||
if (!pid) {
|
||||
for (i = 0; i < loops; i++) {
|
||||
ret = read(pipe_1[0], &m, sizeof(int));
|
||||
ret = write(pipe_2[1], &m, sizeof(int));
|
||||
}
|
||||
} else {
|
||||
for (i = 0; i < loops; i++) {
|
||||
ret = write(pipe_1[1], &m, sizeof(int));
|
||||
ret = read(pipe_2[0], &m, sizeof(int));
|
||||
}
|
||||
}
|
||||
|
||||
gettimeofday(&stop, NULL);
|
||||
timersub(&stop, &start, &diff);
|
||||
|
||||
if (pid)
|
||||
return 0;
|
||||
|
||||
if (simple)
|
||||
printf("%lu.%03lu\n",
|
||||
diff.tv_sec, diff.tv_usec / 1000);
|
||||
else {
|
||||
printf("(executing %d pipe operations between two tasks)\n\n",
|
||||
loops);
|
||||
|
||||
result_usec = diff.tv_sec * 1000000;
|
||||
result_usec += diff.tv_usec;
|
||||
|
||||
printf("\tTotal time:%lu.%03lu sec\n",
|
||||
diff.tv_sec, diff.tv_usec / 1000);
|
||||
printf("\t\t%lf usecs/op\n",
|
||||
(double)result_usec / (double)loops);
|
||||
printf("\t\t%d ops/sec\n",
|
||||
(int)((double)loops /
|
||||
((double)result_usec / (double)1000000)));
|
||||
}
|
||||
|
||||
return 0;
|
||||
}
|
Loading…
Reference in New Issue
Block a user