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afs: Use struct_size() in kzalloc()

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One of the more common cases of allocation size calculations is finding the
size of a structure that has a zero-sized array at the end, along with
memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    void *entry[];
};

instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we can now
use the new struct_size() helper:

instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: David Howells <dhowells@redhat.com>
This commit is contained in:
Gustavo A. R. Silva 2019-01-09 17:23:54 +00:00 committed by David Howells
parent a88cc8da02
commit c2b8bd49d3
1 changed files with 1 additions and 3 deletions
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4
fs/afs/server_list.c
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@ -42,9 +42,7 @@ struct afs_server_list *afs_alloc_server_list(struct afs_cell *cell,
if (vldb->fs_mask[i] & type_mask)
nr_servers++;
slist = kzalloc(sizeof(struct afs_server_list) +
sizeof(struct afs_server_entry) * nr_servers,
GFP_KERNEL);
slist = kzalloc(struct_size(slist, servers, nr_servers), GFP_KERNEL);
if (!slist)
goto error;