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resources: tidy __request_region()
No functional change. Just return NULL for kzalloc failure immediately, rather than wrapping the whole function body in the body of an "if". Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -630,33 +630,34 @@ struct resource * __request_region(struct resource *parent,
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{
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struct resource *res = kzalloc(sizeof(*res), GFP_KERNEL);
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if (res) {
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res->name = name;
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res->start = start;
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res->end = start + n - 1;
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res->flags = IORESOURCE_BUSY;
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if (!res)
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return NULL;
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write_lock(&resource_lock);
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res->name = name;
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res->start = start;
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res->end = start + n - 1;
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res->flags = IORESOURCE_BUSY;
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for (;;) {
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struct resource *conflict;
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write_lock(&resource_lock);
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conflict = __request_resource(parent, res);
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if (!conflict)
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break;
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if (conflict != parent) {
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parent = conflict;
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if (!(conflict->flags & IORESOURCE_BUSY))
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continue;
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}
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for (;;) {
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struct resource *conflict;
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/* Uhhuh, that didn't work out.. */
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kfree(res);
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res = NULL;
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conflict = __request_resource(parent, res);
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if (!conflict)
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break;
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if (conflict != parent) {
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parent = conflict;
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if (!(conflict->flags & IORESOURCE_BUSY))
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continue;
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}
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write_unlock(&resource_lock);
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/* Uhhuh, that didn't work out.. */
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kfree(res);
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res = NULL;
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break;
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}
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write_unlock(&resource_lock);
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return res;
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}
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EXPORT_SYMBOL(__request_region);
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