ptp: free 'vclock_index' in ptp_clock_release()

'vclock_index' is accessed from sysfs, it shouled be freed
in release function, so move it from ptp_clock_unregister()
to ptp_clock_release().

Signed-off-by: Yang Yingliang <yangyingliang@huawei.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Yang Yingliang 2021-10-21 17:13:53 +08:00 committed by David S. Miller
parent bf6abf345d
commit b6b19a71c8

View File

@ -170,6 +170,7 @@ static void ptp_clock_release(struct device *dev)
struct ptp_clock *ptp = container_of(dev, struct ptp_clock, dev);
ptp_cleanup_pin_groups(ptp);
kfree(ptp->vclock_index);
mutex_destroy(&ptp->tsevq_mux);
mutex_destroy(&ptp->pincfg_mux);
mutex_destroy(&ptp->n_vclocks_mux);
@ -286,8 +287,6 @@ struct ptp_clock *ptp_clock_register(struct ptp_clock_info *info,
if (ptp->pps_source)
pps_unregister_source(ptp->pps_source);
kfree(ptp->vclock_index);
if (ptp->kworker)
kthread_destroy_worker(ptp->kworker);
@ -328,8 +327,6 @@ int ptp_clock_unregister(struct ptp_clock *ptp)
ptp->defunct = 1;
wake_up_interruptible(&ptp->tsev_wq);
kfree(ptp->vclock_index);
if (ptp->kworker) {
kthread_cancel_delayed_work_sync(&ptp->aux_work);
kthread_destroy_worker(ptp->kworker);