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mul_u64_u64_div_u64: increase precision by conditionally swapping a and b
As indicated in the added comment, the algorithm works better if b is big. As multiplication is commutative, a and b can be swapped. Do this if a is bigger than b. Link: https://lkml.kernel.org/r/20240303092408.662449-2-u.kleine-koenig@pengutronix.de Signed-off-by: Uwe Kleine-König <u.kleine-koenig@pengutronix.de> Tested-by: Biju Das <biju.das.jz@bp.renesas.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
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@ -22,6 +22,7 @@
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#include <linux/export.h>
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#include <linux/math.h>
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#include <linux/math64.h>
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#include <linux/minmax.h>
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#include <linux/log2.h>
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/* Not needed on 64bit architectures */
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@ -190,6 +191,20 @@ u64 mul_u64_u64_div_u64(u64 a, u64 b, u64 c)
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/* can a * b overflow ? */
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if (ilog2(a) + ilog2(b) > 62) {
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/*
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* Note that the algorithm after the if block below might lose
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* some precision and the result is more exact for b > a. So
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* exchange a and b if a is bigger than b.
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*
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* For example with a = 43980465100800, b = 100000000, c = 1000000000
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* the below calculation doesn't modify b at all because div == 0
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* and then shift becomes 45 + 26 - 62 = 9 and so the result
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* becomes 4398035251080. However with a and b swapped the exact
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* result is calculated (i.e. 4398046510080).
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*/
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if (a > b)
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swap(a, b);
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/*
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* (b * a) / c is equal to
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*
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