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tty: Fix transient pty write() EIO
Commit 699390354d
('pty: Ignore slave pty close() if never successfully opened')
introduced a bug with ptys whereby a write() in parallel with an
open() on an existing pty could mistakenly indicate an I/O error.
Only indicate an I/O error if the condition on open() actually exists.
Reported-by: Markus Trippelsdorf <markus@trippelsdorf.de>
Signed-off-by: Peter Hurley <peter@hurleysoftware.com>
Tested-by: Mikael Pettersson <mikpe@it.uu.se>
Cc: stable <stable@vger.kernel.org> # 3.9
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
parent
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commit
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@ -244,14 +244,9 @@ static void pty_flush_buffer(struct tty_struct *tty)
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static int pty_open(struct tty_struct *tty, struct file *filp)
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{
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int retval = -ENODEV;
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if (!tty || !tty->link)
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goto out;
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return -ENODEV;
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set_bit(TTY_IO_ERROR, &tty->flags);
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retval = -EIO;
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if (test_bit(TTY_OTHER_CLOSED, &tty->flags))
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goto out;
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if (test_bit(TTY_PTY_LOCK, &tty->link->flags))
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@ -262,9 +257,11 @@ static int pty_open(struct tty_struct *tty, struct file *filp)
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clear_bit(TTY_IO_ERROR, &tty->flags);
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clear_bit(TTY_OTHER_CLOSED, &tty->link->flags);
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set_bit(TTY_THROTTLED, &tty->flags);
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retval = 0;
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return 0;
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out:
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return retval;
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set_bit(TTY_IO_ERROR, &tty->flags);
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return -EIO;
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}
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static void pty_set_termios(struct tty_struct *tty,
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