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sock: fix lockdep annotation in release_sock

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During release_sock we use callbacks to finish the processing
of outstanding skbs on the socket. We actually are still locked,
sk_locked.owned == 1, but we already told lockdep that the mutex
is released. This could lead to false positives in lockdep for
lockdep_sock_is_held (we don't hold the slock spinlock during processing
the outstanding skbs).

I took over this patch from Eric Dumazet and tested it.

Signed-off-by: Eric Dumazet <eric.dumazet@gmail.com>
Signed-off-by: Hannes Frederic Sowa <hannes@stressinduktion.org>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Hannes Frederic Sowa 2016-04-05 17:10:14 +02:00 committed by David S. Miller
parent 8501786929
commit 61881cfb5a
2 changed files with 6 additions and 6 deletions
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7
include/net/sock.h
View File

@ -1333,7 +1333,12 @@ static inline void sk_wmem_free_skb(struct sock *sk, struct sk_buff *skb)
static inline void sock_release_ownership(struct sock *sk)
{
sk->sk_lock.owned = 0;
if (sk->sk_lock.owned) {
sk->sk_lock.owned = 0;
/* The sk_lock has mutex_unlock() semantics: */
mutex_release(&sk->sk_lock.dep_map, 1, _RET_IP_);
}
}
/*

5
net/core/sock.c
View File

@ -2483,11 +2483,6 @@ EXPORT_SYMBOL(lock_sock_nested);
void release_sock(struct sock *sk)
{
/*
* The sk_lock has mutex_unlock() semantics:
*/
mutex_release(&sk->sk_lock.dep_map, 1, _RET_IP_);
spin_lock_bh(&sk->sk_lock.slock);
if (sk->sk_backlog.tail)
__release_sock(sk);