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get_task_comm(): return the result
It was dumb to make get_task_comm() return void. Change it to return a pointer to the resulting output for caller convenience. Cc: Ulrich Drepper <drepper@redhat.com> Cc: Ingo Molnar <mingo@elte.hu> Cc: Roland McGrath <roland@redhat.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -947,12 +947,13 @@ static void flush_old_files(struct files_struct * files)
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spin_unlock(&files->file_lock);
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}
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void get_task_comm(char *buf, struct task_struct *tsk)
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char *get_task_comm(char *buf, struct task_struct *tsk)
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{
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/* buf must be at least sizeof(tsk->comm) in size */
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task_lock(tsk);
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strncpy(buf, tsk->comm, sizeof(tsk->comm));
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task_unlock(tsk);
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return buf;
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}
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void set_task_comm(struct task_struct *tsk, char *buf)
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@ -1770,7 +1770,7 @@ extern long do_fork(unsigned long, unsigned long, struct pt_regs *, unsigned lon
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struct task_struct *fork_idle(int);
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extern void set_task_comm(struct task_struct *tsk, char *from);
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extern void get_task_comm(char *to, struct task_struct *tsk);
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extern char *get_task_comm(char *to, struct task_struct *tsk);
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#ifdef CONFIG_SMP
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extern void wait_task_inactive(struct task_struct * p);
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