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MSI: Simplify BUG() handling in pci_disable_msix()
Although it might be nice to do a printk before BUG'ing, it's really not necessary, and it complicates the code. The behaviour has changed slightly, in that before we set a flag if the irq had an action, and continued freeing the other irqs. But as I see it that's all irrelevant because we end up BUG'ing anyway. Signed-off-by: Michael Ellerman <michael@ellerman.id.au> Acked-by: Eric W. Biederman <ebiederm@xmission.com> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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@ -676,7 +676,7 @@ int pci_enable_msix(struct pci_dev* dev, struct msix_entry *entries, int nvec)
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void pci_disable_msix(struct pci_dev* dev)
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{
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int irq, head, tail = 0, warning = 0;
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int irq, head, tail = 0;
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if (!pci_msi_enable)
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return;
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@ -693,19 +693,14 @@ void pci_disable_msix(struct pci_dev* dev)
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irq = head = dev->first_msi_irq;
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while (head != tail) {
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tail = get_irq_msi(irq)->link.tail;
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if (irq_has_action(irq))
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warning = 1;
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else if (irq != head) /* Release MSI-X irq */
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BUG_ON(irq_has_action(irq));
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if (irq != head) /* Release MSI-X irq */
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msi_free_irq(dev, irq);
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irq = tail;
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}
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msi_free_irq(dev, irq);
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if (warning) {
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printk(KERN_WARNING "PCI: %s: pci_disable_msix() called without "
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"free_irq() on all MSI-X irqs\n",
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pci_name(dev));
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BUG_ON(warning > 0);
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}
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dev->first_msi_irq = 0;
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}
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