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bpf: Use pcpu_alloc_size() in bpf_mem_free{_rcu}()
For bpf_global_percpu_ma, the pointer passed to bpf_mem_free_rcu() is allocated by kmalloc() and its size is fixed (16-bytes on x86-64). So no matter which cache allocates the dynamic per-cpu area, on x86-64 cache[2] will always be used to free the per-cpu area. Fix the unbalance by checking whether the bpf memory allocator is per-cpu or not and use pcpu_alloc_size() instead of ksize() to find the correct cache for per-cpu free. Signed-off-by: Hou Tao <houtao1@huawei.com> Link: https://lore.kernel.org/r/20231020133202.4043247-5-houtao@huaweicloud.com Signed-off-by: Alexei Starovoitov <ast@kernel.org>
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@ -11,6 +11,7 @@ struct bpf_mem_caches;
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struct bpf_mem_alloc {
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struct bpf_mem_caches __percpu *caches;
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struct bpf_mem_cache __percpu *cache;
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bool percpu;
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struct work_struct work;
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};
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@ -525,6 +525,7 @@ int bpf_mem_alloc_init(struct bpf_mem_alloc *ma, int size, bool percpu)
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/* room for llist_node and per-cpu pointer */
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if (percpu)
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percpu_size = LLIST_NODE_SZ + sizeof(void *);
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ma->percpu = percpu;
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if (size) {
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pc = __alloc_percpu_gfp(sizeof(*pc), 8, GFP_KERNEL);
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@ -874,6 +875,17 @@ void notrace *bpf_mem_alloc(struct bpf_mem_alloc *ma, size_t size)
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return !ret ? NULL : ret + LLIST_NODE_SZ;
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}
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static notrace int bpf_mem_free_idx(void *ptr, bool percpu)
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{
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size_t size;
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if (percpu)
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size = pcpu_alloc_size(*((void **)ptr));
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else
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size = ksize(ptr - LLIST_NODE_SZ);
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return bpf_mem_cache_idx(size);
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}
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void notrace bpf_mem_free(struct bpf_mem_alloc *ma, void *ptr)
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{
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int idx;
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@ -881,7 +893,7 @@ void notrace bpf_mem_free(struct bpf_mem_alloc *ma, void *ptr)
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if (!ptr)
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return;
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idx = bpf_mem_cache_idx(ksize(ptr - LLIST_NODE_SZ));
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idx = bpf_mem_free_idx(ptr, ma->percpu);
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if (idx < 0)
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return;
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@ -895,7 +907,7 @@ void notrace bpf_mem_free_rcu(struct bpf_mem_alloc *ma, void *ptr)
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if (!ptr)
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return;
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idx = bpf_mem_cache_idx(ksize(ptr - LLIST_NODE_SZ));
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idx = bpf_mem_free_idx(ptr, ma->percpu);
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if (idx < 0)
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return;
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