debugfs: remove module_exit()

debugfs can't be a module, so module_exit() is meaningless for it.

Signed-off-by: WANG Cong <amwang@redhat.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
This commit is contained in:
Amerigo Wang 2011-01-18 13:09:21 -08:00 committed by Greg Kroah-Hartman
parent 345279bc10
commit 1f7da214e2

View File

@ -13,9 +13,6 @@
*
*/
/* uncomment to get debug messages from the debug filesystem, ah the irony. */
/* #define DEBUG */
#include <linux/module.h>
#include <linux/fs.h>
#include <linux/mount.h>
@ -540,17 +537,5 @@ static int __init debugfs_init(void)
return retval;
}
static void __exit debugfs_exit(void)
{
debugfs_registered = false;
simple_release_fs(&debugfs_mount, &debugfs_mount_count);
unregister_filesystem(&debug_fs_type);
kobject_put(debug_kobj);
}
core_initcall(debugfs_init);
module_exit(debugfs_exit);
MODULE_LICENSE("GPL");