um: irq: don't set the chip for all irqs

Setting a chip for an interrupt marks it as allocated. Since UM doesn't
support dynamic interrupt numbers (yet), it means we cannot simply
increase NR_IRQS and then use the free irqs between LAST_IRQ and NR_IRQS
with gpio-mockup or iio testing drivers as irq_alloc_descs() will fail
after not being able to neither find an unallocated range of interrupts
nor expand the range.

Only call irq_set_chip_and_handler() for irqs until LAST_IRQ.

Signed-off-by: Bartosz Golaszewski <bgolaszewski@baylibre.com>
Reviewed-by: Anton Ivanov <anton.ivanov@cambridgegreys.com>
Acked-by: Anton Ivanov <anton.ivanov@cambridgegreys.com>
Signed-off-by: Richard Weinberger <richard@nod.at>
This commit is contained in:
Bartosz Golaszewski 2019-04-11 11:49:44 +02:00 committed by Richard Weinberger
parent ea70d791c1
commit 1987b1b8f9

View File

@ -479,7 +479,7 @@ void __init init_IRQ(void)
irq_set_chip_and_handler(TIMER_IRQ, &SIGVTALRM_irq_type, handle_edge_irq);
for (i = 1; i < NR_IRQS; i++)
for (i = 1; i < LAST_IRQ; i++)
irq_set_chip_and_handler(i, &normal_irq_type, handle_edge_irq);
/* Initialize EPOLL Loop */
os_setup_epoll();