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list.h: add list_cut_position()
This adds list_cut_position() which lets you cut a list into two lists given a pivot in the list. Signed-off-by: Luis R. Rodriguez <lrodriguez@atheros.com> Signed-off-by: John W. Linville <linville@tuxdriver.com>
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@ -214,6 +214,46 @@ static inline int list_is_singular(const struct list_head *head)
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return !list_empty(head) && (head->next == head->prev);
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}
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static inline void __list_cut_position(struct list_head *list,
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struct list_head *head, struct list_head *entry)
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{
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struct list_head *new_first = entry->next;
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list->next = head->next;
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list->next->prev = list;
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list->prev = entry;
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entry->next = list;
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head->next = new_first;
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new_first->prev = head;
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}
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/**
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* list_cut_position - cut a list into two
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* @list: a new list to add all removed entries
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* @head: a list with entries
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* @entry: an entry within head, could be the head itself
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* and if so we won't cut the list
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*
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* This helper moves the initial part of @head, up to and
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* including @entry, from @head to @list. You should
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* pass on @entry an element you know is on @head. @list
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* should be an empty list or a list you do not care about
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* losing its data.
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*
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*/
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static inline void list_cut_position(struct list_head *list,
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struct list_head *head, struct list_head *entry)
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{
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if (list_empty(head))
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return;
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if (list_is_singular(head) &&
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(head->next != entry && head != entry))
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return;
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if (entry == head)
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INIT_LIST_HEAD(list);
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else
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__list_cut_position(list, head, entry);
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}
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static inline void __list_splice(const struct list_head *list,
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struct list_head *prev,
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struct list_head *next)
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